What does pexpect pattern ".+" do?

I have next code:

test.py:

import pexpect
import sys

p = pexpect.spawn("ping 10.192.225.199", encoding="utf-8")
while True:
    try:
        index = p.expect([".+", pexpect.EOF, pexpect.TIMEOUT], timeout=1)
        if index == 0:
            print("===")
            print(p.after)
            print("===")
    except Exception as e:
        print(e)

Execution:

$ python3 test.py
===
PING 10.192.225.199 (10.192.225.199) 56(84) bytes of data.

===
===
64 bytes from 10.192.225.199: icmp_seq=1 ttl=63 time=0.607 ms

===
===
64 bytes from 10.192.225.199: icmp_seq=2 ttl=63 time=0.587 ms

===
...

It looks .+ could fetch the whole line of ping command output during one time iteration.

But, someone suggest this to me, in the official document, it said:

Beware of + and * at the end of patterns
Remember that any time you try to match a pattern that needs look-ahead that you will always get a minimal match (non greedy).
For example, the following will always return just one character:
child.expect ('.+')
This example will match successfully, but will always return no characters:
child.expect ('.*')

What does will always return just one character mean? Why I can get a full line in my minimal example? Isn't it should be one character per loop?

BTW, it's extremely strange that if I change .+ to .*, then just as the document said: will always return no characters. The behavior for .* same as the document said, but .+ not ...

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