python3: extract IP address from compiled pattern

I want to process every line in my log file, and extract IP address if line matches my pattern. There are several different types of messages, in example below I am using p1andp2`.

I could read the file line by line, and for each line match to each pattern. But Since there can be many more patterns, I would like to do it as efficiently as possible. I was hoping to compile thos patterns into one object, and do the match only once for each line:

import re

IP = r'(?P<ip>\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})'

p1 = 'Registration from' + IP + '- Wrong password' 
p2 = 'Call from' + IP + 'rejected because extension not found'

c = re.compile(r'(?:' + p1 + '|' + p2 + ')')

for line in sys.stdin:
    match = re.search(c, line)
    if match:
        print(match['ip'])

but the above code does not work, it complains that ip is used twice.

What is the most elegant way to achieve my goal ?

EDIT:

I have modified my code based on answer from @Dev Khadka.

But I am still struggling with how to properly handle the multiple ip matches. The code below prints all IPs that matched p1:

for line in sys.stdin:
    match = c.search(line)
    if match:
        print(match['ip1'])

But some lines don't match p1. They match p2. ie, I get:

1.2.3.4
None
2.3.4.5
...

How do I print the matching ip, when I don't know wheter it was p1, p2, ... ? All I want is the IP. I don't care which pattern it matched.

from python3: extract IP address from compiled pattern