Get the parent class name of a function with a decorator

Let there be a class with functions:

class Tester:
    
    @Logger()
    def __init__(self):
        print(__class__)
    
    @Logger()
    def func(self, num):
        return num**2

where Logger is a decorator roughly defined as:

from typing import Optional, Any
from logging import getLogger

class Logger:
    def __init__(self):
        self.logger = getLogger()
        self.logging_function = getattr(self, 'function')
        
    def __call__(self, decorator: callable):
        
        def f(*args, **kwargs):
            return self.logging_function(decorator, *args, **kwargs)
        
        return f
    
    def function(self, func: callable, *args: Optional[Any], **kwargs: Optional[Any]):
        func_name = Logger.get_name(func)
        self.logger.info(f"Starting: {func_name}.")
        return func(*args, **kwargs)
    
    @staticmethod
    def get_name(func):
        return f'__init__ {func.__class__.__name__}' if func.__name__ == '__init__' else func.__name__

How can we edit the Logger get_name function, such that if the function being run is a class __init__ that the name returned is __init__ Tester, but if the function is named something else it merely returns the function __name__?

(AKA) Expected output:

>>> test = Tester()
INFO: Starting __init__ Tester.
<class '__main__.Tester'>

>>> test.func(3)
INFO: Starting func. 
9

Current Output:

>>> test = Tester()
INFO: Starting __init__ function.
<class '__main__.Tester'>

>>> test.func(3)
INFO: Starting func. 
9

from Get the parent class name of a function with a decorator