I am trying to create a video conference web app using peer/getUserMedia.
Currently, when I send the unique ID to the video conference, I am able to hear/see anyone who joins my session.
However, only the first person who joins my session can communicate/see me.
I want to make it so the other users can see/hear every user thats in the video conference too.
So far this is what I have working so far. Also the code that is currently written, whenever a new user joins, my video gets added again so I see two videos of myself (if im the host), but that will be an easy fix for me
<html>
<body>
<h3 id="show-peer"></h3>
<div style="display: grid; justify-content: space-around; margin:10px;">
<div style="width: 300px;height: 200px;transform: scale(-1, 1);border: 2px solid; display:grid; margin-bottom: 5%;" id="ourVideo"></div>
<div style="width: 300px;height: 200px;transform: scale(-1, 1);border: 2px solid; display: grid;" id="remoteVideo"></div>
</div>
<input id="peerID" placeholder="Peer ID">
<button id="call-peer" onclick="callPeer()">Call Peer</button>
<br>
<button id="screenShare"onclick="shareScreen()">Share Screen</button>
</body>
<script src="https://unpkg.com/peerjs@1.3.1/dist/peerjs.min.js"></script>
<script>
window.addEventListener('load',(event)=>{
var peer= new Peer()
var myStream;
var currentPeer;
var peerList=[];
peer.on('open',function(id){
document.getElementById("show-peer").innerHTML=id
})
peer.on('call',function(call){
navigator.mediaDevices.getUserMedia({
video:true,
audio:true
}).then((stream)=>{
myStream = stream
addOurVideo(stream)
call.answer(stream)
call.on('stream',function(remoteStream){
if(!peerList.includes(call.peer)){
addRemoteVideo(remoteStream)
currentPeer = call.peerConnection
peerList.push(call.peer)
}
})
}).catch((err)=>{
console.log(err+" unable to get media")
})
})
function stopScreenShare(){
let videoTrack = myStream.getVideoTracks()[0];
var sender = currentPeer.getSenders().find(function(s){
return s.track.kind ==videoTrack.kind;
})
sender.replaceTrack(videoTrack)
};
document.getElementById("call-peer").addEventListener('click',(e)=>{
let remotePeerId= document.getElementById("peerID").value;
document.getElementById("show-peer").innerHTML= "connecting "+remotePeerId;
console.log(remotePeerId)
callPeer(remotePeerId);
})
document.getElementById("screenShare").addEventListener('click',(e)=>{
navigator.mediaDevices.getDisplayMedia({
video: {
cursor: "always"
},
audio:{
autoGainControl: false,
echoCancellation: false,
googAutoGainControl: false,
noiseSuppression: false
}
}).then((stream)=>{
let videoTrack = stream.getVideoTracks()[0];
videoTrack.onended = function(){
stopScreenShare()
}
let sender = currentPeer.getSenders().find(function(s){
return s.track.kind == videoTrack.kind
})
sender.replaceTrack(videoTrack)
}).catch((err)=>{
console.log("unable to get display media"+err)
})
})
function callPeer(id){
navigator.mediaDevices.getUserMedia({
video:true,
audio:true
}).then((stream)=>{
myStream = stream
addOurVideo(stream)
let call = peer.call(id,stream)
call.on('stream',function(remoteStream){
if(!peerList.includes(call.peer)){
addRemoteVideo(remoteStream)
currentPeer = call.peerConnection
peerList.push(call.peer)
}
})
}).catch((err)=>{
console.log(err+" unable to get media")
})
}
function addRemoteVideo(stream){
let video = document.createElement("video");
video.classList.add("video")
video.srcObject = stream;
video.play()
document.getElementById("remoteVideo").append(video)
}
function addOurVideo(stream){
let video = document.createElement("video");
video.classList.add("video")
video.srcObject = stream;
video.play()
video.muted=true;
document.getElementById("ourVideo").append(video)
}
});
</script>
</html>
from Video/Audio communication
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