Navigation component - how to check whether the fragment is newly navigated to vs. poped back to

When using the Navigation component, it is simple to navigate to the next fragment and also simple to pop back to the previous fragment.

Navigation.findNavController(v).navigate(R.id.action1);
/*vs*/
Navigation.findNavController(v).popBackStack();

How can I check within onViewCreated() how startDestination / topLevel destination fragments were reached? If it was poped back to I want to run different code compared to when it was newly navigated to.

---

Update thanks to @Thracian for the suggestions:

I tested:

navController.addOnDestinationChangedListener(new NavController.OnDestinationChangedListener() {
        @Override
        public void onDestinationChanged(@NonNull NavController controller, @NonNull NavDestination destination, @Nullable Bundle arguments) {
            Log.d("MAIN", "New destination ID: " + destination.getDisplayName());
        }
    });

But it returns the same result, whether I directly navigate to a fragment or use popBack/navigateUp, so it does not help to distinguish.

I tested:

navHostFragment = (NavHostFragment) getSupportFragmentManager().findFragmentById(R.id.nav_host_fragment);
    navHostManager = navHostFragment.getChildFragmentManager();
    navHostManager.addOnBackStackChangedListener(new FragmentManager.OnBackStackChangedListener() {
        @Override
        public void onBackStackChanged() {
            int backStackEntryCount = navHostManager.getBackStackEntryCount();
            int fragmentCount = navHostManager.getFragments().size();

            Log.e("MAIN","backStackEntryCount: "+backStackEntryCount+", fragmentCount: " + fragmentCount);
        }
    });

Unfortunately the fragment I try to solve this for is the startDestination. Hence the backStackEntryCount is always 0 when I reach it, both for navigateTo and for navigateUp ...

For my other top-level destinations this does also not properly work, as they always show backStackEntryCount = 1 independent of how I reach them.

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