The book Introduction to Probability by Blitzstein and Hwang provides an example of combinations using ice cream.
- The first level is cone: Waffle or Cake
- The second level is flavour: chocolate, vanilla or strawberry
The basic example is 2 * 3 = 6 separate choices.
I can represent each level of choice separately:
from sympy.functions.combinatorial.numbers import nC
from sympy.utilities.iterables import combinations, combinations_with_replacement
cones = combinations('CW', 1)
list(cones)
>>> [('C',), ('W',)]
flavours = combinations('cvs', 1)
list(flavours)
>>> [('c',), ('v',), ('s',)]
# how to get a list representing all choices? (Cc, Cv, Cs, Wc, Wv, Ws)
# how to return a count of the choices, e.g. with nC()?
I was wondering if it is possible to combine the levels with sympy and return a list of each combination and a count of the available combinations?
from How to represent multiple level combinations?
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